We solve this integral using the substitution method. = sin -1x (x) - ∫ (1 / √(1 - x²)) x dx (Using the formula of derivative of sin inverse x) Then by using the formula of integration by parts: By ILATE rule, the first function = sin -1x and the second function = 1. For this, we write ∫ sin -1x dx as ∫ sin -1x Let us prove that ∫ sin⁻¹x dx = x sin -1x + √(1 - x²) + C.
Here are the proofs of inverse trig integrals. To evaluate each of the above integrals, we assume the first function as the respective inverse trig function and the second function as 1. How to Find Integrals of Inverse Trig Functions?Īs mentioned earlier, we use the integration by parts to evaluate the integrals of inverse trig functions.
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